8x^2+4x+6=1

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Solution for 8x^2+4x+6=1 equation: 



8x^2+4x+6=1

We move all terms to the left:

8x^2+4x+6-(1)=0

We add all the numbers together, and all the variables

8x^2+4x+5=0

a = 8; b = 4; c = +5;
Δ = b2-4ac
Δ = 42-4·8·5
Δ = -144
Delta is less than zero, so there is no solution for the equation

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